Blade Disc
The circular blade on a radial arm saw is turning at 265rad/s. Find net torque.?
The circular blade on a radial arm saw is turning at 265 rad/s at the instant the motor is turned off. In 12.0 s the speed of the blade is reduced to 85 rad/s. Assume the blade to be a uniform solid disk of radius 0.140 m and mass 0.400 kg. Find the net torque applied to the blade.
If T is torque, I is moment of inertia, and a is angular acceleration,
T = Ia (looks a lot like F = ma, yeah?)
Integrating (or using the equation for velocity vs time, if this is calculus-free physics),
v = v0 + at
where v is angular velocity at time t, v0 is the initial velocity, and angular acceleration is given above. combining the two equations,
v = v0 + (T/I)t = (265 /s) + [ T/ (1/2 mr^2) ] * (12 s) = 85 /s
where m=0.4 kg is the mass of the disk of radius r=0.14 m. Solve for torque T.
m
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